Unzipping on sys Platforms

Flustix · January 17, 2022, 6:14pm

i’ve been trying to unzip a file on haxe but i cant find a way because all the functions are not available on sys platforms

tjrhodes · January 17, 2022, 8:25pm

Hi,

You could try something like this instead:

File.saveBytes(zipPath, zipBytes);
Sys.command("unzip",['-qq','-o',zipPath,'-d',scanDir]);
// cycle through zip and store paths to individual scans.
recursiveLoop(scanDir);

tokiop · January 17, 2022, 8:50pm

There is also an example on code.haxe.org !

ianharrigan · January 20, 2022, 9:39am

Ive been using this without issue (so far):

github.com

ianharrigan/hvm/blob/main/hvm/HVM.hx#L863-L910

    
      
          // https://gist.github.com/ruby0x1/8dc3a206c325fbc9a97e
          private static function unzipFile(srcZip:String, dstDir:String, ignoreRootFolder:Bool = false) {
              log("Unzipping archive");
              FileSystem.createDirectory(dstDir);
              
              var inFile = sys.io.File.read(srcZip);
              var entries = haxe.zip.Reader.readZip(inFile);
              inFile.close();
          
          
    for(entry in entries) {
                  var fileName = entry.fileName;
                  if (fileName.charAt(0) != "/" && fileName.charAt(0) != "\\" && fileName.split("..").length <= 1) {
                      var dirs = ~/[\/\\]/g.split(fileName);
                      if ((ignoreRootFolder != false && dirs.length > 1) || ignoreRootFolder == false) {
                          if (ignoreRootFolder != false) {
                              dirs.shift();
                          }
                      
                          var path = "";
                          var file = dirs.pop();

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tjrhodes · January 20, 2022, 11:18am

I thought the OP was talking about a situation where the haxe method didn’t work on sys targets. Ian’s way is best, using the Reader if you can…